-30x^2+35x=0

Solution for -30x^2+35x=0 equation:

-30x^2+35x=0

a = -30; b = 35; c = 0;
Δ = b2-4ac
Δ = 352-4·(-30)·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-35}{2*-30}=\frac{-70}{-60}
=1+1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+35}{2*-30}=\frac{0}{-60}
=0
$